tristan/tools
1
0
Fork 0
Code Issues Pull requests Projects Releases Packages Wiki Activity Actions

Refactor zipremove.py to process all ZIP files in a directory

Browse source
This commit is contained in:
Tristan Smith 2024-04-05 23:16:37 -04:00
parent 808370ef1f
commit 6b6c06d0e5
1 changed files with 11 additions and 8 deletions
Show stats Download patch file Download diff file Expand all files Collapse all files

17
zipremove.py
View file

@ -2,27 +2,30 @@ import zipfile
import os
import sys
import tempfile
from pathlib import Path
def filter_and_repack_zip(zip_path):
# Temporary directory to hold the contents we want to keep
temp_dir = tempfile.TemporaryDirectory()
new_zip_path = os.path.join(temp_dir.name, 'new_archive.zip')
with zipfile.ZipFile(zip_path, 'r') as original_zip:
with zipfile.ZipFile(new_zip_path, 'w') as new_zip:
for file in original_zip.namelist():
# Conditions for keeping the file
if "(USA" in file or "(USA, Europe)" in file:
new_zip.writestr(file, original_zip.read(file))
# Replace the original zip file with the new one
os.replace(new_zip_path, zip_path)
def process_directory(directory_path):
for zip_file in Path(directory_path).glob('*.zip'):
print(f"Processing {zip_file}")
filter_and_repack_zip(zip_file)
print("All ZIP files processed.")
if __name__ == "__main__":
if len(sys.argv) != 2:
print("Usage: python script.py <zip_file_path>")
print("Usage: python script.py <directory_path>")
sys.exit(1)
zip_file_path = sys.argv[1]
filter_and_repack_zip(zip_file_path)
print(f"Processed {zip_file_path}")
directory_path = sys.argv[1]
process_directory(directory_path)