Merge pull request '046: Show usage of .? and hint towards new solution.' (#116) from alexmchughnz/ziglings:fix046 into main

Reviewed-on: https://codeberg.org/ziglings/exercises/pulls/116
This commit is contained in:
Chris Boesch 2024-06-24 19:13:25 +00:00
commit f496d79ab9
2 changed files with 27 additions and 12 deletions

View file

@ -5,7 +5,7 @@
// linked to the first elephant. This is because we had NO CONCEPT
// of a tail that didn't point to another elephant!
//
// We also introduce the handy ".?" shortcut:
// We also introduce the handy `.?` shortcut:
//
// const foo = bar.?;
//
@ -13,7 +13,8 @@
//
// const foo = bar orelse unreachable;
//
// See if you can find where we use this shortcut below.
// Check out where we use this shortcut below to change control flow
// based on if an optional value exists.
//
// Now let's make those elephant tails optional!
//
@ -31,14 +32,25 @@ pub fn main() void {
var elephantC = Elephant{ .letter = 'C' };
// Link the elephants so that each tail "points" to the next.
elephantA.tail = &elephantB;
elephantB.tail = &elephantC;
linkElephants(&elephantA, &elephantB);
linkElephants(&elephantB, &elephantC);
// `linkElephants` will stop the program if you try and link an
// elephant that doesn't exist! Uncomment and see what happens.
// const missingElephant: ?*Elephant = null;
// linkElephants(&elephantC, missingElephant);
visitElephants(&elephantA);
std.debug.print("\n", .{});
}
// If e1 and e2 are valid pointers to elephants,
// this function links the elephants so that e1's tail "points" to e2.
fn linkElephants(e1: ?*Elephant, e2: ?*Elephant) void {
e1.?.*.tail = e2.?;
}
// This function visits all elephants once, starting with the
// first elephant and following the tails to the next elephant.
fn visitElephants(first_elephant: *Elephant) void {
@ -51,6 +63,9 @@ fn visitElephants(first_elephant: *Elephant) void {
// We should stop once we encounter a tail that
// does NOT point to another element. What can
// we put here to make that happen?
// HINT: We want something similar to what `.?` does,
// but instead of ending the program, we want to exit the loop...
e = e.tail ???
}
}

View file

@ -1,18 +1,18 @@
--- exercises/046_optionals2.zig 2024-05-10 23:11:25.796632478 +0200
+++ answers/046_optionals2.zig 2024-05-10 23:10:16.115335668 +0200
@@ -21,7 +21,7 @@
--- exercises/046_optionals2.zig 2024-06-23 19:43:16
+++ answers/046_optionals2.zig 2024-06-23 19:42:46
@@ -22,7 +22,7 @@
const Elephant = struct {
letter: u8,
- tail: *Elephant = null, // Hmm... tail needs something...
+ tail: ?*Elephant = null, // <---- make this optional!
+ tail: ?*Elephant = null, // Hmm... tail needs something...
visited: bool = false,
};
@@ -51,6 +51,6 @@
// We should stop once we encounter a tail that
// does NOT point to another element. What can
// we put here to make that happen?
@@ -66,6 +66,6 @@
// HINT: We want something similar to what `.?` does,
// but instead of ending the program, we want to exit the loop...
- e = e.tail ???
+ e = e.tail orelse break;
}