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Merge pull request '046: Show usage of .?
and hint towards new solution.' (#116) from alexmchughnz/ziglings:fix046 into main
Reviewed-on: https://codeberg.org/ziglings/exercises/pulls/116
This commit is contained in:
commit
f496d79ab9
2 changed files with 27 additions and 12 deletions
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@ -5,7 +5,7 @@
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// linked to the first elephant. This is because we had NO CONCEPT
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// of a tail that didn't point to another elephant!
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//
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// We also introduce the handy ".?" shortcut:
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// We also introduce the handy `.?` shortcut:
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//
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// const foo = bar.?;
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//
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@ -13,7 +13,8 @@
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//
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// const foo = bar orelse unreachable;
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//
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// See if you can find where we use this shortcut below.
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// Check out where we use this shortcut below to change control flow
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// based on if an optional value exists.
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//
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// Now let's make those elephant tails optional!
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//
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@ -31,14 +32,25 @@ pub fn main() void {
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var elephantC = Elephant{ .letter = 'C' };
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// Link the elephants so that each tail "points" to the next.
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elephantA.tail = &elephantB;
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elephantB.tail = &elephantC;
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linkElephants(&elephantA, &elephantB);
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linkElephants(&elephantB, &elephantC);
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// `linkElephants` will stop the program if you try and link an
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// elephant that doesn't exist! Uncomment and see what happens.
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// const missingElephant: ?*Elephant = null;
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// linkElephants(&elephantC, missingElephant);
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visitElephants(&elephantA);
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std.debug.print("\n", .{});
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}
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// If e1 and e2 are valid pointers to elephants,
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// this function links the elephants so that e1's tail "points" to e2.
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fn linkElephants(e1: ?*Elephant, e2: ?*Elephant) void {
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e1.?.*.tail = e2.?;
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}
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// This function visits all elephants once, starting with the
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// first elephant and following the tails to the next elephant.
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fn visitElephants(first_elephant: *Elephant) void {
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@ -51,6 +63,9 @@ fn visitElephants(first_elephant: *Elephant) void {
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// We should stop once we encounter a tail that
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// does NOT point to another element. What can
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// we put here to make that happen?
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// HINT: We want something similar to what `.?` does,
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// but instead of ending the program, we want to exit the loop...
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e = e.tail ???
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}
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}
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@ -1,18 +1,18 @@
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--- exercises/046_optionals2.zig 2024-05-10 23:11:25.796632478 +0200
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+++ answers/046_optionals2.zig 2024-05-10 23:10:16.115335668 +0200
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@@ -21,7 +21,7 @@
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--- exercises/046_optionals2.zig 2024-06-23 19:43:16
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+++ answers/046_optionals2.zig 2024-06-23 19:42:46
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@@ -22,7 +22,7 @@
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const Elephant = struct {
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letter: u8,
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- tail: *Elephant = null, // Hmm... tail needs something...
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+ tail: ?*Elephant = null, // <---- make this optional!
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+ tail: ?*Elephant = null, // Hmm... tail needs something...
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visited: bool = false,
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};
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@@ -51,6 +51,6 @@
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// We should stop once we encounter a tail that
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// does NOT point to another element. What can
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// we put here to make that happen?
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@@ -66,6 +66,6 @@
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// HINT: We want something similar to what `.?` does,
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// but instead of ending the program, we want to exit the loop...
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- e = e.tail ???
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+ e = e.tail orelse break;
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}
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