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Added epic ex058 - quiz 7

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Dave Gauer 2021-04-04 16:05:44 -04:00
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5
build.zig
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@ -297,6 +297,11 @@ const exercises = [_]Exercise{
.main_file = "057_unions3.zig", .main_file = "057_unions3.zig",
.output = "Insect report! Ant alive is: true. Bee visited 17 flowers.", .output = "Insect report! Ant alive is: true. Bee visited 17 flowers.",
}, },
.{
.main_file = "058_quiz7.zig",
.output = "Archer's Point--2->Bridge--1->Dogwood Grove--3->Cottage--2->East Pond--1->Fox Pond",
.hint = "This is the biggest program we've seen yet. But you can do it!"
},
}; };
/// Check the zig version to make sure it can compile the examples properly. /// Check the zig version to make sure it can compile the examples properly.

458
exercises/058_quiz7.zig Normal file
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@ -0,0 +1,458 @@
//
// We've absorbed a lot of information about the variations of types
// we can use in Zig. Roughly, in order we have:
//
// u8 single item
// *u8 single-item pointer
// []u8 slice (size known at runtime)
// [5]u8 array of 5 u8s
// [*]u8 many-item pointer (zero or more)
// enum {a, b} set of unique values a and b
// error {e, f} set of unique error values e and f
// struct {y: u8, z: i32} group of values y and z
// union(enum) {a: u8, b: i32} single value either u8 or i32
//
// Values of any of the above types can be assigned as "var" or "const"
// to allow or disallow changes (mutability) via the assigned name:
//
// const a: u8 = 5; // immutable
// var b: u8 = 5; // mutable
//
// We can also make error unions or optional types from any of
// the above:
//
// var a: E!u8 = 5; // can be u8 or error from set E
// var b: ?u8 = 5; // can be u8 or null
//
// Knowing all of this, maybe we can help out a local hermit. He made
// a little Zig program to help him plan his trips through the woods,
// but it has some mistakes.
//
const print = @import("std").debug.print;
// The grue is a nod to Zork.
const TripError = error{ Unreachable, EatenByAGrue };
// Let's start with the Places on the map. Each has a name and a
// distance or difficulty of travel (as judged by the hermit).
//
// Note that we declare the places as mutable (var) because we need to
// assign the paths later. And why is that? Because paths contain
// pointers to places and assigning them now would create a dependency
// loop!
const Place = struct {
name: []const u8,
paths: []const Path = undefined,
};
var a = Place{ .name = "Archer's Point" };
var b = Place{ .name = "Bridge" };
var c = Place{ .name = "Cottage" };
var d = Place{ .name = "Dogwood Grove" };
var e = Place{ .name = "East Pond" };
var f = Place{ .name = "Fox Pond" };
// The hermit's hand-drawn ASCII map
// +---------------------------------------------------+
// | * Archer's Point ~~~~ |
// | ~~~ ~~~~~~~~ |
// | ~~~| |~~~~~~~~~~~~ ~~~~~~~ |
// | Bridge ~~~~~~~~ |
// | ^ ^ ^ |
// | ^ ^ / \ |
// | ^ ^ ^ ^ |_| Cottage |
// | Dogwood Grove |
// | ^ <boat> |
// | ^ ^ ^ ^ ~~~~~~~~~~~~~ ^ ^ |
// | ^ ~~ East Pond ~~~ |
// | ^ ^ ^ ~~~~~~~~~~~~~~ |
// | ~~ ^ |
// | ^ ~~~ <-- short waterfall |
// | ^ ~~~~~ |
// | ~~~~~~~~~~~~~~~~~ |
// | ~~~~ Fox Pond ~~~~~~~ ^ ^ |
// | ^ ~~~~~~~~~~~~~~~ ^ ^ |
// | ~~~~~ |
// +---------------------------------------------------+
//
// We'll be reserving memory in our program based on the number of
// places on the map. Note that we do not have to specify the type of
// this value because we don't actually use it in our program once
// it's compiled! (Don't worry if this doesn't make sense yet.)
const place_count = 6;
// Now let's create all of the paths between sites. A path goes from
// one place to another and has a distance.
const Path = struct {
from: *const Place,
to: *const Place,
dist: u8,
};
// By the way, if the following code seems like a lot of tedious
// manual labor, you're right! One of Zig's killer features is letting
// us write code that runs at compile time to "automate" repetitive
// code (much like macros in other languages), but we haven't learned
// how to do that yet!
const a_paths = [_]Path{
Path{
.from = &a, // from: Archer's Point
.to = &b, // to: Bridge
.dist = 2,
},
};
const b_paths = [_]Path{
Path{
.from = &b, // from: Bridge
.to = &a, // to: Archer's Point
.dist = 2,
},
Path{
.from = &b, // from: Bridge
.to = &d, // to: Dogwood Grove
.dist = 1,
},
};
const c_paths = [_]Path{
Path{
.from = &c, // from: Cottage
.to = &d, // to: Dogwood Grove
.dist = 3,
},
Path{
.from = &c, // from: Cottage
.to = &e, // to: East Pond
.dist = 2,
},
};
const d_paths = [_]Path{
Path{
.from = &d, // from: Dogwood Grove
.to = &b, // to: Bridge
.dist = 1,
},
Path{
.from = &d, // from: Dogwood Grove
.to = &c, // to: Cottage
.dist = 3,
},
Path{
.from = &d, // from: Dogwood Grove
.to = &f, // to: Fox Pond
.dist = 7,
},
};
const e_paths = [_]Path{
Path{
.from = &e, // from: East Pond
.to = &c, // to: Cottage
.dist = 2,
},
Path{
.from = &e, // from: East Pond
.to = &f, // to: Fox Pond
.dist = 1, // (one-way down a short waterfall!)
},
};
const f_paths = [_]Path{
Path{
.from = &f, // from: Fox Pond
.to = &d, // to: Dogwood Grove
.dist = 7,
},
};
// Once we've plotted the best course through the woods, we'll make a
// "trip" out of it. A trip is a series of Places connected by Paths.
// We use a TripItem union to allow both Places and Paths to be in the
// same array.
const TripItem = union(enum) {
place: *const Place,
path: *const Path,
// This is a little helper function to print the two different
// types of item correctly. Note how this "print()" is namespaced
// to the TripItem union and doesn't interfere with calling the
// "print()" from the standard library we imported at the top of
// this program.
fn print(self: TripItem) void {
switch (self) {
// Oops! The hermit forgot how to capture the union values
// in a switch statement. Please capture both values as
// 'p' so the print statements work!
.place => print("{s}", .{p.name}),
.path => print("--{}->", .{p.dist}),
}
}
};
// The Hermit's Notebook is where all the magic happens. A notebook
// entry is a Place discovered on the map along with the Path taken to
// get there and the distance to reach it from the start point. If we
// find a better Path to reach a Place (lower distance), we update the
// entry. Entries also serve as a "todo" list which is how we keep
// track of which paths to explore next.
const NotebookEntry = struct {
place: *const Place,
coming_from: ?*const Place,
via_path: ?*const Path,
dist_to_reach: u16,
};
// +------------------------------------------------+
// | ~ Hermit's Notebook ~ |
// +---+----------------+----------------+----------+
// | | Place | From | Distance |
// +---+----------------+----------------+----------+
// | 0 | Archer's Point | null | 0 |
// | 1 | Bridge | Archer's Point | 2 | < next_entry
// | 2 | Dogwood Grove | Bridge | 1 |
// | 3 | | | | < end_of_entries
// | ... |
// +---+----------------+----------------+----------+
//
const HermitsNotebook = struct {
// Remember the array repetition operator `**`? It is no mere
// novelty, it's also a great way to assign multiple items in an
// array without having to list them one by one. Here we use it to
// initialize an array with null values.
entries: [place_count]?NotebookEntry = .{null} ** place_count,
// The next entry keeps track of where we are in our "todo" list.
next_entry: u8 = 0,
// Mark the start of empty space in the notebook.
end_of_entries: u8 = 0,
// We'll often want to find an entry by Place. If one is not
// found, we return null.
fn getEntry(self: *HermitsNotebook, place: *const Place) ?*NotebookEntry {
for (self.entries) |*entry, i| {
if (i >= self.end_of_entries) break;
// Here's where the hermit got stuck. We need to return
// an optional pointer to a NotebookEntry.
//
// What we have with "entry" is the opposite: a pointer to
// an optional NotebookEntry!
//
// To get one from the other, we need to dereference
// "entry" (with .*) and get the non-null value from the
// optional (with .?) and return the address of that. The
// if statement provides some clues about how the
// dereference and optional value "unwrapping" look
// together. Remember that you return the address with the
// "&" operator.
if (place == entry.*.?.place) return entry;
// Try to make your answer this long:__________;
}
return null;
}
// The checkNote() method is the beating heart of the magical
// notebook. Given a new note in the form of a NotebookEntry
// struct, we check to see if we already have an entry for the
// note's Place.
//
// If we DON'T, we'll add the entry to the end of the notebook
// along with the Path taken and distance.
//
// If we DO, we check to see if the path is "better" (shorter
// distance) than the one we'd noted before. If it is, we
// overwrite the old entry with the new one.
fn checkNote(self: *HermitsNotebook, note: NotebookEntry) void {
var existing_entry = self.getEntry(note.place);
if (existing_entry == null) {
self.entries[self.end_of_entries] = note;
self.end_of_entries += 1;
} else if (note.dist_to_reach < existing_entry.?.dist_to_reach) {
existing_entry.?.* = note;
}
}
// The next two methods allow us to use the notebook as a "todo"
// list.
fn hasNextEntry(self: *HermitsNotebook) bool {
return self.next_entry < self.end_of_entries;
}
fn getNextEntry(self: *HermitsNotebook) *const NotebookEntry {
defer self.next_entry += 1; // Increment after getting entry
return &self.entries[self.next_entry].?;
}
// After we've completed our search of the map, we'll have
// computed the shortest Path to every Place. To collect the
// complete trip from the start to the destination, we need to
// walk backwards from the destination's notebook entry, following
// the coming_from pointers back to the start. What we end up with
// is an array of TripItems with our trip in reverse order.
//
// We need to take the trip array as a parameter because we want
// the main() function to "own" the array memory. What do you
// suppose could happen if we allocated the array in this
// function's stack frame (the space allocated for a function's
// "local" data) and returned a pointer or slice to it?
//
// Looks like the hermit forgot something in the return value of
// this function. What could that be?
fn getTripTo(self: *HermitsNotebook, trip: []?TripItem, dest: *Place) void {
// We start at the destination entry.
const destination_entry = self.getEntry(dest);
// This function needs to return an error if the requested
// destination was never reached. (This can't actually happen
// in our map since every Place is reachable by every other
// Place.)
if (destination_entry == null) {
return TripError.Unreachable;
}
// Variables hold the entry we're currently examining and an
// index to keep track of where we're appending trip items.
var current_entry = destination_entry.?;
var i: u8 = 0;
// At the end of each looping, a continue expression increments
// our index. Can you see why we need to increment by two?
while (true) : (i += 2) {
trip[i] = TripItem{ .place = current_entry.place };
// An entry "coming from" nowhere means we've reached the
// start, so we're done.
if (current_entry.coming_from == null) break;
// Otherwise, entries have a path.
trip[i + 1] = TripItem{ .path = current_entry.via_path.? };
// Now we follow the entry we're "coming from". If we
// aren't able to find the entry we're "coming from" by
// Place, something has gone horribly wrong with our
// program! (This really shouldn't ever happen. Have you
// checked for grues?)
const previous_entry = self.getEntry(current_entry.coming_from.?);
if (previous_entry == null) return TripError.EatenByAGrue;
current_entry = previous_entry.?;
}
}
};
pub fn main() void {
// Here's where the hermit decides where he would like to go. Once
// you get the program working, try some different Places on the
// map!
const start = &a; // Archer's Point
const destination = &f; // Fox Pond
// Store each Path array as a slice in each Place. As mentioned
// above, we needed to delay making these references to avoid
// creating a dependency loop when the compiler is trying to
// figure out how to allocate space for each item.
a.paths = a_paths[0..];
b.paths = b_paths[0..];
c.paths = c_paths[0..];
d.paths = d_paths[0..];
e.paths = e_paths[0..];
f.paths = f_paths[0..];
// Now we create an instance of the notebook and add the first
// "start" entry. Note the null values. Read the comments for the
// checkNote() method above to see how this entry gets added to
// the notebook.
var notebook = HermitsNotebook{};
var working_note = NotebookEntry{
.place = start,
.coming_from = null,
.via_path = null,
.dist_to_reach = 0,
};
notebook.checkNote(working_note);
// Get the next entry from the notebook (the first being the
// "start" entry we just added) until we run out, at which point
// we'll have checked every reachable Place.
while (notebook.hasNextEntry()) {
var place_entry = notebook.getNextEntry();
// For every Path that leads FROM the current Place, create a
// new note (in the form of a NotebookEntry) with the
// destination Place and the total distance from the start to
// reach that place. Again, read the comments for the
// checkNote() method to see how this works.
for (place_entry.place.paths) |*path| {
working_note = NotebookEntry{
.place = path.to,
.coming_from = place_entry.place,
.via_path = path,
.dist_to_reach = place_entry.dist_to_reach + path.dist,
};
notebook.checkNote(working_note);
}
}
// Once the loop above is complete, we've calculated the shortest
// path to every reachable Place! What we need to do now is set
// aside memory for the trip and have the hermit's notebook fill
// in the trip from the destination back to the path. Note that
// this is the first time we've actually used the destination!
var trip = [_]?TripItem{null} ** (place_count * 2);
notebook.getTripTo(trip[0..], destination) catch |err| {
print("Oh no! {}\n", .{err});
return;
};
// Print the trip with a little helper function below.
printTrip(trip[0..]);
}
// Remember that trips will be a series of alternating TripItems
// containing a Place or Path from the destination back to the start.
// The remaining space in the trip array will contain null values, so
// we need to loop through the items in reverse, skipping nulls, until
// we reach the destination at the front of the array.
fn printTrip(trip: []?TripItem) void {
var i: u8 = @intCast(u8, trip.len); // convert usize length
while (i > 0) {
i -= 1;
if (trip[i] == null) continue;
trip[i].?.print();
}
print("\n", .{});
}
// Going deeper:
//
// In computer science terms, our map places are "nodes" or "vertices" and
// the paths are "edges". Together, they form a "weighted, directed
// graph". It is "weighted" because each path has a distance (also
// known as a "cost"). It is "directed" because each path goes FROM
// one place TO another place (undirected graphs allow you to travel
// on an edge in either direction).
//
// Since we append new notebook entries at the end of the list and
// then explore each sequentially from the beginning (like a "todo"
// list), we are treating the notebook as a "First In, First Out"
// (FIFO) queue.
//
// Since we examine all closest paths first before trying further ones
// (thanks to the "todo" queue), we are performing a "Breadth-First
// Search" (BFS). By tracking "lowest cost" paths, we can also say
// that we're performing a "least-cost search".
//
// Even more specifically, the Hermit's Notebook most closely
// resembles the Shortest Path Faster Algorithm (SPFA), attributed to
// Edward F. Moore. By replacing our simple FIFO queue with a
// "priority queue", we would basically have Dijkstra's algorithm. A
// priority queue retrieves items sorted by "weight" (in our case, it
// would keep the paths with the shortest distance at the front of the
// queue). Dijkstra's algorithm is more efficient because longer paths
// can be eliminated more quickly. (Work it out on paper to see why!)

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patches/patches/058_quiz7.patch Normal file
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@ -0,0 +1,14 @@
188,189c188,189
< .place => print("{s}", .{p.name}),
< .path => print("--{}->", .{p.dist}),
---
> .place => |p| print("{s}", .{p.name}),
> .path => |p| print("--{}->", .{p.dist}),
251c251
< if (place == entry.*.?.place) return entry;
---
> if (place == entry.*.?.place) return &entry.*.?;
305c305
< fn getTripTo(self: *HermitsNotebook, trip: []?TripItem, dest: *Place) void {
---
> fn getTripTo(self: *HermitsNotebook, trip: []?TripItem, dest: *Place) TripError!void {